st={"name":"xxx","emails":["a@123.com","b@123.com"],"age":20}del st["emails"][0]st["emails"].append("c@123.com")del st["age"]print(st)结果是
A、{'name': 'xxx', 'emails': ['b@123.com', 'c@123.com']};
B、{'name': 'xxx', 'emails': ['a@123.com','b@123.com', 'c@123.com']};
C、{'name': 'xxx', 'emails': ['a@123.com','a@123.com', 'c@123.com'],"age":20};
D、{'name': 'xxx', 'emails': ['a@123.com','a@123.com', 'c@123.com']}
发布时间:2025-07-28 14:45:59