298K,p(O2)=100kPa条件下,O2+4H++4e- = 2H2O的电极电势为
A、j /V=jy/V +(0.0591pH)/V;
B、j/V =jy/ V –(0.0591V pH)/V;
C、j/V =jy/V +(0.0148V pH)/V;
D、j/V =jy/V –(0.0148V pH)/V
发布时间:2025-08-19 16:20:11
A、j /V=jy/V +(0.0591pH)/V;
B、j/V =jy/ V –(0.0591V pH)/V;
C、j/V =jy/V +(0.0148V pH)/V;
D、j/V =jy/V –(0.0148V pH)/V