答案:答: (1) 多级错流萃取过程计算。首先,溶质在两相中的分配服从分配定律。设各级萃取中溶剂的用量相等,则第一级的物料衡算式为
VKXzCvPePQzT0Ntvz9kNDrpdj3SDh3h1oHwWgcZWmH8Fq-h7geSWgFDyozAavKur
因为XP89tM_okYhpQFGKdiGR824QAyCPmTBWZ15vVVAjP6HrtFizIeOAzslr_oYu-62L, 所以DHGftN6aAHVCjhQPppa8oZW_NDkvXWRUxfCyLS_JOxkHrEfUwMT_sSlzQsu5DSNT6HXytH1uo_WvQAgF5ocDFg则
55IYwefGpyyp_PM8Yqht2E5uNi92jb3MuP6RoV4N8-Q
依此计算第二级, 得
_fD68bAIlQljdnp-WVqhOTgx5MtaRNR3wuI-WyK83oq6FxyK0tPTxQbTAKLB-_3X
同理, 对第dhexd0YHgG8oWh1T_Sn8zA级, 得
4ig9bFVa5QYlOq5jvzbycFOFApU-HKC9kfe9asIBNzqu8RdEUC_TF2RwLJWuXedWa6LfuOp5iWGdQ0rwSgHgrTznQm13L116JE0B0DeMJoIY-15L5dS1IIuBysa_wk1y
解方程式可求出理论级数竹, 为
wbhZASFmATxKj3ctez6mGUAQNfG3kyrinzQG7Y3mdrX6Gdtdug8-1fNGj9ZtG2hbetD7RsYd6dzPfilPdUcN4QEsZ9tlZnpqvBBd2a5j0RY
过程的萃取分率或收率为
pGGD03EmLDAVXHqPSfC1tI7kRFZHPVN2e3gtGMID3Y-zCAnuVoRhb_D4r7UbA09W
而末被萃取分率为
36MWFPU4dyp_2n-OIzojCAtJVmxyHFomOWBBsAZEUh8T0kBHu7YH0wyqLj3KFygOQnAPoF58MBSE7aH5EcDpJA对于第vXK9hk70a1dnR3y7BiaZeA级, 平衡线及操作方程分別为
UD5Uh4Sf0JOreHxD3gt15qERFWOqow019PNexpjRivGxAaIR2p6q0xVgBMPK_lVcanpvoIKFwNTt9Ks8Tba1DkL_cTLscZPix5Ab59LDFy1zLS176HtZngolidbhuBKd_GGo1HG29MAskguN2dO4BA
对于第 1 级, 由于z96UkFYFEcxmQDNDAHqptARYHuhXwwujEYMa9Lu7i3s, 可以解得
hucXzGOIm1deqhbDBioZ_FW-bMfX8H_Sg1X-qEI467M
对于第 2 级, 有
kVBWBu8r9EertnufMihpxEYJEhUFHap0pi0B9u2-0LTZx9f30KocupomMhBRYPYsE6nBUSD7PvbYYzavpMiZIg
依此类推, 对于第dhexd0YHgG8oWh1T_Sn8zA级
ImrbzUILDz0j1ddM5evPjo9q6krYvqUSXqRXAv9N0Hbty0J06LRhBDU10BbxV9STZ2Kgr_dUO44iWNnI1ER4Kw
多级逆流萃取过程的萃取分率为
b5smecgimMZTxZ269BKckf5obbe3dcMQei3_28Nr59iXpqm_bbVOtbTNHdnI4AMk1ECybbz__5FO2wL6Ri1Uquhf6cLO9RO-Ce9xLLMSSNixzNKgqq6w22Ida4y4r2ljnQQOxRNOI64L8UUlh5RNng
末被萃取分率为
36MWFPU4dyp_2n-OIzojCG1PX2UHYBOnn9Y1JCEarOAzUFeubNS0jskkbK6tRX5w